LifeTally
Tsarin lissafin layi mai abubuwa biyu da ba a sani ba
Shin lissafin layinka biyu suna da mafita ɗaya, babu mafita, ko mafita marasa iyaka?
Shigar da ƙimomi shida na ax + by = c da dx + ey = f. Gano nau’in mafita da x da y idan mafitar guda ɗaya ce.
Lissafin layinka biyu
Yi amfani da ax + by = c da dx + ey = f, da ƙimomin dindindin a dama. Ka tabbatar da ma’anar masu ninkawa da ma’aunan sun dace. Rubuta kaso a desimal, ba a/b ba.
Yadda ake samun kimantawa
D = ae − bd. Idan D ≠ 0, x = (ce − bf)/D da y = (af − cd)/D. Idan D = 0, ana duba ko lissafin sun dace dabam. Idan a, b, d da e duk sifili ne, mafita marasa iyaka suna samuwa ne kawai idan c = f = 0. A sauran yanayi, dole ce − bf da af − cd duka su zama sifili domin samun mafita marasa iyaka; in ba haka ba babu mafita. Rarrabawa tana buƙatar duk ƙimomi shida ingantattu; D yana buƙatar a, b, d da e kawai.
ax + by = c; dx + ey = f
D = ae − bd
D ≠ 0: x = (ce − bf) ÷ D; y = (af − cd) ÷ DLissafin layi biyu da aka bayar a lambobin ainihi kawai, har da layin sifili 0 = 0 da saɓani kamar 0 = 1. Idan mafita ba su da iyaka, ba a nuna ƙa’idar da ke da ma’aunin canji ko wani sashen daidaitaccen wurin x ko y ba. Babu manyan tsarin lissafi, lissafin da ba na layi ba, rashin daidaito, amsar lambobin hadaddun ko alamomi, jadawalin zane, daidaita bayanai, sauya ma’auni, tantance aunawa, kimanta rashin tabbas ko tabbacin zahiri ko tsaro.
OpenStax: determinant da ƙa’idar Cramer ↗OpenStax: tsarin lissafin layi da nau’in mafita ↗
Duba misalin da aka cika
Misalinmu: 2x − y = 7 da x + 3y = 0. D = 7, x = 3, y = −1. Saka ƙimomin yana ba da 2×3 − (−1) = 7 da 3 + 3×(−1) = 0. Waɗannan zaɓaɓɓun ƙimomin misalin lissafi ne, ba ƙa’idojin ma’auni ko hasashe ba.
Ƙimomin da aka karɓa
- Lissafi na farko: a
- 2
- Lissafi na farko: b
- -1
- Lissafi na farko: c
- 7
- Lissafi na biyu: d
- 1
- Lissafi na biyu: e
- 3
- Lissafi na biyu: f
- 0
Shirya mataki na gaba
Yi amfani da kalkuletar yau da kullum domin ayyukan lissafi dabam. Duba ko lissafin biyu suna bayyana matsalar da kake nufi.
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